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ludmilkaskok [199]
3 years ago
5

A large university accepts ​60% of the students who apply. Of the students the university​ accepts, ​45% actually enroll. If 20,

000 students​ apply, how many actually​ enroll?
Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

444 because 20000 divided by 45 is 444

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Yasmin purchased 6 heads of cabbage that each weighed 2 and StartFraction 3 over 8 EndFraction pounds. How much did the cabbage
alexdok [17]

Answer: 4/10

Step-by-step explanation: easy

6/2=4  

8/2=4X10=40 .  

now...

40/4= 10

so its simply 4/10

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-5(6y + 4) + 25 = 15(2y + 5) + 73
Nataly_w [17]

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y = - 143/60 = -2 23/60

Step-by-step explanation:

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2 years ago
A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N. A new batch of yarn was made, usin
AlexFokin [52]

Answer:

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal variables:

When we subtract two normal variables, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N.

This means that \mu_1 = 6.1, s_1 = \frac{0.7}{\sqrt{125}} = 0.0626

In a sample of 75 pieces of yarn from the new batch, the mean breaking strength was 5.8 N and the standard deviation was 1.0 N.

This means that \mu_2 = 5.8, s_2 = \frac{1}{\sqrt{75}} = 0.1155

Distribution of the difference:

\mu = \mu_1 - \mu_2 = 6.1 - 5.8 = 0.3

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0626^2+0.1155^2} = 0.1314

Confidence interval:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs

M = 1.645*0.1314 = 0.22

The lower end of the interval is the sample mean subtracted by M. So it is 0.3 - 0.22 = 0.08N

The upper end of the interval is the sample mean added to M. So it is 0.3 + 0.22 = 0.52N

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

3 0
3 years ago
Gianna is paid $90 for 5 hours of work.<br><br> • How much money does Gianna make per hour?
Montano1993 [528]

Answer:

18 dollars per hour

Step-by-step explanation:

6 0
3 years ago
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PLEASE HELP ME WITH THIS PLEASE!
sukhopar [10]

Answer:

Area of a rectangle is Width * Length

Apply this to each area the question asks for

AreaTop = 8cm * 4cm = 32cm^{2}

AreaBottom = the same, 32cm^{2}

AreaFront = 2cm * 4cm = 8cm^{2}

AreaBack = the same, 8cm^{2}

AreaLeftSide = 2cm * 8cm = 16cm^{2}

AreaRightSide = the same, 16cm^{2}

TotalSurfaceArea = 16 + 16 + 8 + 8 + 32 + 32 = 112cm^{2}

4 0
4 years ago
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