Answer:
3.97 x 10²³atoms
Explanation:
Given parameters:
Mass of ammonia = 11.22g
Unknown:
Chemical amount of ammonia present = ?
Solution:
The chemical amount present in a substance is the number of atoms it contains.
To solve this problem, from the given mass find the number of moles first.
Number of moles =
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles = = 0.66mole
1 mole of any substance contains 6.02 x 10²³ atoms
0.66 mole of ammonia will contain 0.66 x 6.02 x 10²³ atoms
= 3.97 x 10²³atoms
Yes it should have the same mass
Answer : The excess reactant in the combustion of methane in opem atmosphere is molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,
First we have to calculate the moles of methane.
= = 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is molecule.
repeat the experiment would be the easiest way to make sure u got the correct and accurate answer
It's a mixture becuase it is a substance made by mixing other substances togrther such as flour, sugar, and eggs.