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3 years ago

Methane is a colorless, odorless gas. it oxidizes in air and has a boiling point of -161Â°

Chemistry

2 answers:

Vinvika [58]3 years ago

8 0

Answer : The chemical property of methane is, Oxidizes in air.

Explanation :

Physical property : It can be observed or measured when no changes occurs in the chemical composition of the substance.

For example : color, boiling point, melting point, odor, density, etc.

Chemical property : It can be observed or measured when changes occurs by the chemical reaction in the composition of the substance.

For example : oxidation, combustion, toxicity, rusting, etc.

From the given options, methane oxidizes in the air shows the chemical property. While the other options, colorless, odorless and boiling point shows the physical property.

When methane react with oxygen to produce carbon dioxide and water.

$CH_4(g)+O_2(g)\rightarrow CO_2(g)+H_2O(l)$

Therefore, the correct answer is, Oxidize in air.

Katyanochek1 [597]3 years ago

5 0

Answer: oxidizes in air

Explanation: Chemical property is the property which deals with change in chemical composition of the substance.

Physical change is the property which deals with change in physical state of the substance.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

The above equation represents the oxidation of methane to form carbon dioxide and water. Thus the chemical composition has changed and is a chemical property.

Color and odor only involves no change in chemical composition.

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Consider the following system at equilibrium:

alexgriva [62]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and reduce (q) to one third

Explanation:

<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>

P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.

In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.

Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.

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3 years ago

WILL GIVE BRAINLIEST! Explain how a pure metal is held together. Include a definition of a metallic bond in your explanation. Pl

vazorg [7]

Explanation:

A chemical bond which is formed in between positively charged atoms when there is sharing of free electrons in a lattice of cations is known as a metallic bond.

In a pure metal, atoms are surrounded by free moving valence electrons which move from one part of metal to another.

Thus, we can conclude that pure metals are held together by metallic bonds due to attraction between mobile valence electrons and positively charged metal ions.

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3 years ago

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The answer please thank you

otez555 [7]

Answer:

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3 years ago

If a gas in a box with fixed volume has a pressure of 913 torr at 15 C, what temperature should the gas be heated to double the

algol13

<span>700 mL hop it helps u ok</span>