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3 years ago

Earl runs 75 meters in 30 seconds. How many meters does Earl run per second?

Mathematics

1 answer:

enyata [817]3 years ago

5 0

Average speed: distance traveled/elapsed time

= 75/30

= 2.5 meters per second.

Best of Luck!

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two classmates have decided to read all the volumes in a popular series of books. Katie has already read 4 volumes and will cont

scoray [572]

To solve this we can make it into an equation, which looks like this

y = 2x (for Rebecca)
y = x + 10 (for Alice)

The we subtract one equation from the other to solve

0 = x - 10
10 = x
x = 10

Now we replace x in whichever equation and we get 20

So, each girl will read 20 books for them to be at the same book.

Hope this helps, remember that Jesus loves you

5 0

2 years ago

In triangle MPN, angle P is a right angle. If cos N= 3/5 which of the following statements is true

Bezzdna [24]

Answer: Sin N = $\frac{4}{5}$

Step-by-step explanation:

Since we have given that

In triangle MPN, ∠P=90°

$\cos N=\frac{3}{5}$

As we know the formula for "Trigonometric Ratios":

$\cos N=\frac{Base}{Hypotenuse}=\frac{3}{5}$

By Pythagorus theorem , we get

$H^2=B^2+P^2\\\\5^2=3^2+P^2\\\\25=9+P^2\\\\25-9=P^2\\\\16=P^2\\\\P=\sqrt{16}\\\\P=4\ units$

So, we get,

$\sin N=\frac{Perpendicular}{Hypotenuse}=\frac{4}{5}$

Hence, Sin N = $\frac{4}{5}$

3 0

3 years ago

Find the indicated sum for each sequence. S9 of –9, 36, –144, 576, ...

gogolik [260]

This is a geometric sequence with a common ratio of -4:

-9*-4=36

36*-4=-144

-144*-4=576

Thus, the 9th term would be equal to:

(-4)^5*576 which is -589824

The exponent 5 comes from the fact that 4 terms have already been displayed and we need 9-4 more terms to get to the 9th term. Since we are multiplying by -4 only, the 5 remains an exponent

5 0

3 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

2 years ago

Which two statements about conditional probability are true?

allochka39001 [22]

I believe the answer is C and F.

Hope this helps!

8 0

3 years ago