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Anna [14]
2 years ago
6

What is the distance between the points (4, -2) and (-1, 10)?

Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0

Answer:

13 units.

Step-by-step explanation:

We can find distance between points by using the following formula:

\sqrt{(change in x)^2+(changeiny)^2}

The change in x is -5, and change in y is 12. Let's apply this to the formula.

\sqrt{(-5)^2+(12)^2}. Evaluate this, and we get 13.

Hope this helped!

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Olve for x. Check each step or answer that is correct. 34(x + 4) = 14(x + 8) (A) Distribute 34 on the left side of the equation.
Fantom [35]

Answer:

x = -1.2

Step-by-step explanation:

Th given equation is :

34(x + 4) = 14(x + 8)

Step (A) Distribute 34 on the left side of the equation such as :

34x + 34(4) = 14(x + 8)

34x + 136 = 14(x + 8)

Step (B) Distribute 14 on the right side of the equation such as :

34x + 136 = 14x + 14(8)

34x + 136 = 14x + 112

Step (C) Subtract 14x from each side of the equation.

34x + 136 - 14x = 14x + 112 -14x

20x + 136 = 112

Step (D) Subtract 136 from each side of the equation.

20x + 136 -136 = 112 -136

20x = -24

Step (E) Divide both side by 20

\dfrac{20x}{20}=\dfrac{-24}{20}\\\\x=-1.2

So, the value of x is (-1.2). Hence, steps (D) and (E) are incorrect.

3 0
3 years ago
Points (5, 3) and (6, 2) lie on line k. Which is the slope of the line that is parallel to k
BARSIC [14]
Can you add a picture?
5 0
3 years ago
Three is no less than a number x<br> .
Pie

Step-by-step explanation:

if three(3) is not less than x, this means it's more than x so it'll be 3+x

5 0
2 years ago
Owen can jog 660 yards in 3 minutes. how many yards would you expect him to jog in 10 minutes?
pshichka [43]

Answer: 2200 yards

Step-by-step explanation:

First find the unit rate, 660/3 = 220

So, Owen can jog 220 yards in one minute.

220 times 10 to find how much Owen can jog in 10 minutes.

220*10 = 2200.

6 0
1 year ago
Suppose that circles R and S have a central angle measuring 80°. Additionally, circle R has a radius of 3 ft and the radius of c
DerKrebs [107]

Let 

rA--------> radius of the circle R

rB-------> radius of the circle S

SA------> the area of the sector for circle R

SB------> the area of the sector for circle S

 

we have that

rA=3 ft

rB=6 ft

rA/rB=3/6----> 1/2-----------> rB/rA=2

SA=2π ft²

 

we know that

 

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

 

(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(2) ^2*(2π)--->

SB----------- > 8π ft²


the answer is

the area of the sector for circle S is 8π ft²


8 0
2 years ago
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