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3 years ago

There are 6 gr of fat in 1/4 cup of cheese. How many gr. Of fat are in 1/2 cup of cheese?

2 answers:

5 0

A lot of people are going to be the only one who has been on the same page as the other one of the most important things that I have ever seen on the show and I love the fact that I have a lot of friends and I have no idea what I want to do with my life and I don't have to be a good person and I don't have to be a good person and I don't have to be a good person and I don't have to be a good

ale4655 [162]3 years ago

4 0

Answer= 12 Gr OF FAT.. If 6 in 1/4. 4 quarters make a whole .

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3 years ago

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

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3 years ago