Answer:
-15
Step-by-step explanation:
We proceed as follows;
In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.
Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.
Thus, we have;
2a(b-3) + 5b + _
Now, putting -15 will give us the same expression in the first bracket and this gives us the following;
2a(b-3) + 5b-15
2a(b-3) + 5(b-3)
So we can have ; (2a+5)(b-3)
Hence the constant used is -15
Sorry is this some sort of equation I’m confused
Answer:
y = -5/2x - 13
Step-by-step explanation:
First, we have to find the slope of the original equation
Subtract 5x from both sides
5x + 2y = 1
- 5x - 5x
2y = -5x + 1
Divide both sides by 2
2y/2 = (-5x + 1)/2
y = -5/2x + 1/2
The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation
y = -5/2x + b
Plug in the given x and y
-3 = -5/2(-2) + b
-3 = 10 + b
Subtract 10 from both sides
-3 = 10 + b
- 10 - 10
b = -13
This makes our equation: y = -5/2x - 13
I think this is the correct answer: * Zc x (sigma/sqrt of n)
c= .95 (Zc of 1.96)
0.711*
