Answer:
A Marco le sobra 400.
Step-by-step explanation:
Marco gana 1200 mensualmente. La mitad de su dinero es entregado a su mamá.
La mitad de un número se calcula dividiendo el número por 2. Por lo que la mitad de lo ganado por Marco se calcula:
1200 ÷2= 600
Por lo que Marco entrega a su mamá 600 mensualmente, y quedan 600, obtenido de la resta entre lo ganado mensualmente y lo entregado a su madre.
De lo que le queda gasta en la tercera parte en ropa. La tercera parte de un número se calcula dividiendo el número por 3. Entonces:
600 ÷3= 200
Entonces Marco gasta 200 en ropa. Por lo que resta es 400, obtenido por la diferencia entre los 600 que poseía luego de entregar dinero a su madre y lo gastado en ropa.
Entonces, <u><em>a Marco le sobra 400.</em></u>
Answer:
x=59/5 or x=11.8 depends on which one you want to do both are true
Step-by-step explanation:
Start with what you are given
angle 4= 5x+6 and angle 3=65 because lines m and n are both parallel angle4=angle3 in other words 5x+6=65
what you want to do is get x by itself.
1. Subtract 6 from both sides
5x+6-6=65-6
5x=59
2. Divide both sides by 5
5x/5=59/5
x=59/5
3. Check to see if you can simplify the fraction and if you teacher wants it in decimals or exact fraction.
x=59/5 or x=11.8 they are the same just ones a decimal the other is left as a fraction
Use a proportion.
121/16.5 = 22/m
121m = 16.5 * 22
11m = 16.5 * 2
11m = 33
m = 3
3 minutes.
Given:
The piecewise function is

To find:
The range of given piecewise function.
Solution:
Range is the set of output values.
Both functions
and
as linear functions.
Starting value of
is at x=-4 and end value is at x=3.
Starting value: 
End value: 
Starting value of
is at x=3 and end value is at x=6.
Starting value: 
End value: 
Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.
Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.
So, the range of the given piecewise function is [0,11).
Therefore, the correct option is A.