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juin [17]
3 years ago
9

Pls help me: A couple plans to have 4 children. The gender of each child is equally likely. Design a simulation involving 90 tri

als that you can use to model the genders of the children, you do not need to generate the numbers or find the probability, just explain how your simulation would work. You should include information like how many digits long each number is, which digits represent a boy child and which digits represent a girl. also show the step by step of how to ans this.
Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

The simulation of the gender of a child by the couple is an illustration of probability.

<h3>How to design a simulation?</h3>

The number of trials (n) is given as:

n = 90

The chance of getting each gender is equal.

So, we have:

P(Boy) = 0.5

P(Girl) = 0.5

The simulation would be based on numbers 0 to 9. Such that:

  • The numbers 0 to 4 represent a boy child
  • The numbers 5 to 9 represent a girl child

Notice that each gender have the same amount of digits i.e. 5

This is so because they both have equal chance

Read more about probability at:

brainly.com/question/251701

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Express 2x+1/(x-2)(x²+1) as a partial fraction.
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Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

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Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

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A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

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simplify

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C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

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Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

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