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lara31 [8.8K]
2 years ago
14

You can use the ____ method to search a string to determine whether it contains a specific sequence of characters.

Computers and Technology
1 answer:
kherson [118]2 years ago
6 0

Answer:

in

Explanation:

Not an explanation, but here's an example:

if "mouth" in "mouthwatering":

   print("It is.")

else:

   pass

Another example:

if "water" in "mouthwatering":

   print("Yes.")

else:

   pass

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Write a test program that creates two Rectangle objects—one with width 4 and height 40 and the other with width 3.5 and height 3
BARSIC [14]

Answer:

public class Rectangle {

   private double width;

   private double heigth;

   public Rectangle(double width, double heigth) {

       this.width = width;

       this.heigth = heigth;

   }

   public double getWidth() {

       return width;

   }

   public void setWidth(double width) {

       this.width = width;

   }

   public double getHeigth() {

       return heigth;

   }

   public void setHeigth(double heigth) {

       this.heigth = heigth;

   }

   public double perimeter(double width, double heigth){

       double peri = 2*(width+heigth);

       return peri;

   }

   public double area(double width, double heigth){

       double area = width*heigth;

       return  area;

   }

}

class RectangleTest{

   public static void main(String[] args) {

       //Creating two Rectangle objects

       Rectangle rectangle1 = new Rectangle(4,40);

       Rectangle rectangle2 = new Rectangle(3.5, 35.7);

       //Calling methods on the first Rectangel objects

       System.out.println("The Height of Rectangle 1 is: "+rectangle1.getHeigth());

       System.out.println("The Width of Rectangle 1 is: "+rectangle1.getWidth());

       System.out.println("The Perimeter of Rectangle 1 is: "+rectangle1.perimeter(4,40));

       System.out.println("The Area of Rectangle 1 is: "+rectangle1.area(4,40));

       // Second Rectangle object

       System.out.println("The Height of Rectangle 2 is: "+rectangle2.getHeigth());

       System.out.println("The Width of Rectangle 2 is: "+rectangle2.getWidth());

       System.out.println("The Perimeter of Rectangle 2 is: "+rectangle2.perimeter(4,40));

       System.out.println("The Area of Rectangle 2 is: "+rectangle2.area(4,40));

   }

}

Explanation:

  • Firstly A Rectangle class is created with two fields for width and heigth, a constructor and getters and setters the class also has methods for finding area and perimeters
  • Then a RectangleTest class containing a main method is created and two Rectangle objects are created (Follow teh comments in the code)
  • Methods to get height, width, area and perimeter are called on each rectangle object to print the appropriate value
5 0
2 years ago
How does one build social capital?
iren2701 [21]

Answer:

by building on line presence

Explanation:

If you put yourself out there in multiple social sites you will build a following

3 0
2 years ago
What steps can be used to password-protect a worksheet?
muminat

Answer:

Review

Changes

Protect sheet

Explanation:

I did it

8 0
3 years ago
Imagine that you need to be late to work next Thursday because of a doctor's appointment. Compose your own e-mail appropriate fo
ratelena [41]
In form your boss a week early
8 0
3 years ago
Write a Java method to delete a record from a B-tree of order n.
max2010maxim [7]

Answer:

Deleting a record on a B-tree consists of three main events:

- Searching the node where the key to be deleted exists

- Deleting the key

- Balancing the tree if required

Explanation:

q = NULL;

   p = tree;

   while (p) {

       i = nodesearch(p, key);

       q = p;

       if (i < used(p) -1 && key == k(p,i)) {

           found = TRUE;

           position = i;

           break;

       }

       p = son(p,i);

   }

   if (!found)

   else if (subtree(p)) {

         if (used(p) > ((n-1)/2)+1)

         delkey (p, position, key);

       else {

           replace (p, position, fsucc(p));

           p0 r1 p1 r2 p2 r3 ……. pn-1 rn-1 pn

           q = &fsucc(p);

           qpos = index of fsucc;

           if (used(rbrother(p)) > ((n-1)/2)+1)

               replace (q, qpos, sonsucc(q));

           else

               while (q && used(q) < (n-1)/2) {

                   concatenate(q, brother(q));

                   q = father(q);

               }

       }

   }

   else

   delkey(p, position, key);

}

6 0
3 years ago
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