Answer:
135°
Step-by-step Explanation:
==>Given:
An inscribed quadrilateral ABCD with,
m<A = (3x +6)°
m<C = (x + 2)°
==>Required:
measure of angle A
==>Solution:
First, let's find the value of x.
Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.
Therefore, this means m<A + m<C = 180°
Thus, (3x+6) + (x+2} = 180
3x + 6 + x + 2 = 180
Collect like terms:
3x + x + 6 + 2 = 180
4x + 8 = 180
Subtract 8 from both sides:
4x + 8 - 8 = 180 - 8
4x = 172
Divide both sides by 4:
4x/4 = 172/4
x = 43
We can now find m<A = (3x + 6)°
m<A = 3(43) + 6
= 129 + 6
measure of angle A = 135°
<em>11</em>
5 pound = 500 pence
500 pence/ 45 pence= 11.1111111
12 and 13 have the same amount of students. so B or C will work. please mark brainliest
Answer:
y = 6x + 28
Step-by-step explanation:
We are to determine the equation of a line whose slope or gradient is 6 and passes through the point (-4, 4)
The slope-intercept form of the equation of the straight line would be given by;
y = mx + c
y = 6x + c
We proceed to use the given point to determine c;'
when x = -4, y = 4
4 = 6(-4) + c
4 = -24 + c
c = 28
The slope-intercept form of the equation of the straight line is thus;
y = 6x + 28
