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2 years ago

How do you integrate 7xe^-5x²?

1 answer:

3 0

Making assumptions about where parentheses should be,
Let u = -7x 
du = -7dx 
dv = e^(2x) dx 
v = e^(2x)/2 
∫ -7xe^(2x) dx = 
-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = 
-7xe^(2x)/2 + 7e^(2x)/4 + c

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Which of the following shows the graph of y = 4x 3? on a coordinate plane, an exponential function starts at y = 3 in quadrant 2

ZanzabumX [31]

The graph of the linear equation y = 4x + 3 can be seen at the end of the answer.

<h3>How to find the graph of the given line?</h3>

Here we have the linear equation:

y = 4x + 3.

To graph it, we need to find two points that belong to the line, to do that, we evaluate in two different values of x. I will use x = 0 and x = 2.

When x = 0.

y = 4*0 + 3 = 3

So we have the point (0, 3).

When x = 2:

y = 4*2 + 3 = 8 + 3 = 11

So we have the point (2, 11)

Now we just need to graph these two points and connect them with a line. The graph of the linear equation is the one you can see below.

If you want to learn more about linear equations:

brainly.com/question/1884491

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5 0

1 year ago

IF YOU ARE UNSURE PLEASE DO NOT ANSWER!!! According to the graph, how long would it take to travel 26 miles?

tatyana61 [14]

It is a. i am sure the answer is a

7 0

2 years ago

VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.

mario62 [17]

Answer:

Coordinates switch, and the new y-coordinate changes sign

Explanation:

We have point A with the coordinates (-1,2), when we rotate it c90º it becomes (2,1).

What happened? The coordinates switched and the x-coordinate of A (-1) became the y-coordinate of A' (1) and it changed its sign.

7 0

2 years ago

Read 2 more answers

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

1 year ago

Suppose △LMN≅△PQR .

Tanya [424]

First four answers are correct as congruent parts of congruent triangles are congruent but L Is not the opposite to M so they wouldn’t be congruent nor does NL or PQ have the same connection

6 0

2 years ago