How do you integrate 7xe^-5x²?

1 answer:

3 0

Making assumptions about where parentheses should be,
Let u = -7x 
du = -7dx 
dv = e^(2x) dx 
v = e^(2x)/2 
∫ -7xe^(2x) dx = 
-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = 
-7xe^(2x)/2 + 7e^(2x)/4 + c

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