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Marysya12 [62]
3 years ago
14

The trapezoid in the figure has equal nonparallel sides. The upper base is 6, the lower base is 16, and the diagonal is 12. What

is the altitude of the trapezoid?
A. 7.9
B. 4.8
C. 5.7
D. 8.4

Mathematics
1 answer:
____ [38]3 years ago
5 0

To find this I would use the pythagorean theorem which is:

a^2 + b^2 = c^2

Since we already know c = hypotenuse, and a side of the shorter sides we can plug them it like this:

11^2 + b^2 = 12^2

121 + b^2 = 144

b^2 = 23

√23 = 4.79

Round:

B. 4.8 would be your answer!

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Which sampling would be appropriate to survey 120,000 people?
kipiarov [429]

Answer: Id say b

Step-by-step explanation: a would be too high and a bit too detailed. Whereas c and d will be inaccurate.

8 0
3 years ago
Find the volume of the sphere.
maria [59]

I hope this helps you

V of Sphere =4/3.pi.r^3

r=1

V=4/3.3,14.1^3

V=4,1866666

8 0
3 years ago
Ab^2-4/10 when a=4 b=6
hammer [34]

\huge\text{Hey there!}

\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}

\large\boxed{\rm{6^2}}

\large\boxed{\rm{= 6 \times6}}

\large\boxed{\rm{= \bf 36}}

\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}

\large\boxed{\rm{4(36)}}

\large\boxed{\rm{= \bf 144}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}

\large\boxed{\rm{\bold{144} - 4}}

\large\boxed{= \rm{\bf 140}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}

\large\boxed{\rm{= \bf 14}}

\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

4 0
2 years ago
PLease hellp meeeeeeeee
g100num [7]

Answer:

I think it -2 then -7

6 0
3 years ago
If your starting salary is $40,000 and you  receive a 4.2% raise every year, how much  TOTAL money will you make in 15 years?
Oliga [24]
The first year, the amount is 40,000

the second year is 40000 + 4.2% of 40000, or 0.042 * 4000, so 40000+(0.042*4000)
common factoring that  we get 40000(1 + 0.042), or just 40000(1.042)

in short, the starting amount is 40000, and to get the next term's value you'd use the "common ratio" of 1.042, namely the multiplier of 1.042.

for the third year it'll be 40000(1.042) + (0.042 *40000(1.042) ), again, common factoring that

40000(1.042)(1 + 0.042) or 40000(1.042)(1.042) or 40000(1.042)²

therefore,

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=40000\\
r=1.042\\
n=15
\end{cases}
\\\\\\
S_{15}=40000\left( \cfrac{1-1.042^{15}}{1-1.042} \right)\implies S_{15}\approx 40000\left( \cfrac{-0.8536}{-0.042} \right)
\\\\\\
S_{15}\approx 812951.42
5 0
3 years ago
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