Surface area of the square pyramid = 217.8 in²
Solution:
Side length of the square = 9 in
Area of the square = side × side
= 9 in × 9 in
= 81 in²
Area of the square = 81 in²
Perimeter of the base = 4 × 9 in = 36 in
Slant height of the triangle = 7.6 in
Surface area of the square pyramid
= 217.8 in²
Surface area of the square pyramid = 217.8 in²
1/4 = 3/12
3/12 < 5/12
Therefore, 5/12 is greater than 1/4
Answer:
A = 82.53 in²
Step-by-step explanation:
We use the circumference equation C = 2πr and the area equation A = πr².
Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.
C 32 in
C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in
2π 6.28
Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²
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