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Marysya12 [62]
3 years ago
14

The trapezoid in the figure has equal nonparallel sides. The upper base is 6, the lower base is 16, and the diagonal is 12. What

is the altitude of the trapezoid?
A. 7.9
B. 4.8
C. 5.7
D. 8.4

Mathematics
1 answer:
____ [38]3 years ago
5 0

To find this I would use the pythagorean theorem which is:

a^2 + b^2 = c^2

Since we already know c = hypotenuse, and a side of the shorter sides we can plug them it like this:

11^2 + b^2 = 12^2

121 + b^2 = 144

b^2 = 23

√23 = 4.79

Round:

B. 4.8 would be your answer!

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A cylindrical candle has a volume of approximately 400cm^3 and is 8 cm tall. What is the radius of the candle?
katrin2010 [14]

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

We know that

V = πr²h

400 = 22/7 × r² × 8

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2800 = 154r²

2800/154 = r²

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-8u = -7u+ 5<br> U=<br> Help
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3 0
2 years ago
The coordinates of the midpoint of gh are m(-13/2,-6) and the coordinates of one endpoint are g(-4,1). what is the other endpoin
Alex777 [14]

Applying the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

<h3>How to Apply the Midpoint Formula?</h3>

The midpoint formula, which can be used in determining the coordinates of the midpoint between two endpoints is usually expressed as: M[(x1 + x2)/2, (y1 + y2)/2].

Given the following coordinates:

Midpoint of GH --> m(-13/2,-6) = (x, y)

One endpoint ---> G(-4, 1) = (x1, y1)

The other endpoint ---> (x2, y2)

Plug in the values into the formula used in calculating the midpoint:

m(-13/2,-6) = [(-4 + x2)/2, (1 + y2)/2]

Solve for x2

-13/2 = (-4 + x2)/2

-13/2 × 2 = -4 + x2

-13 = -4 + x2

-13 + 4 = x2

-9 = x2

x2 = -9

Solve for y2

-6 = (1 + y2)/2

2(-6) = 1 + y2

-12 = 1 + y2

-12 - 1 = y2

-13 = y2

y2 = -13

Thus, using the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

Learn more about the midpoint formula on:

brainly.com/question/13115533

#SPJ1

4 0
1 year ago
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