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rusak2 [61]
2 years ago
14

Please help me with this

Mathematics
2 answers:
klio [65]2 years ago
6 0
The answer is 117. 90+27 = 117.
Roman55 [17]2 years ago
5 0

Answer:

Step-by-step explanation:

Always use PEMDAS.

3³ = 27

30 ÷ 5 = 6

15 x 6 = 90

90 + 27 =  117

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Determine which of these quantities DOES combine to make 0. A) Buying 24 pencils and giving 22 pencils away B) Losing $20.00 and
EleoNora [17]

D) Picking up 12 kids for a party and then dropping 12 kids off at the pool

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Subtract 8-4 1/2. A. 3 B. 4 C. 4 1/2 D. 3 1/2
Leokris [45]
1.
An expression of the form a \frac{b}{c} is called a "compound fraction"
 
Compound fractions can be written as simple fractions by multiplying c to a, and then adding the product to c as follows:

a \frac{b}{c}= \frac{c.a+b}{c}

for example, 

4\frac{1}{2} can be written as: 

4\frac{1}{2}= \frac{2.4+1}{2}=\frac{9}{2}

2.

when we subtract or add a fraction \frac{m}{n} from an integer k, 

we first write k as a fraction with denominator n. We can do this as follows:

k=k. \frac{n}{n}= \frac{kn}{n}

for example, if we want to subtract \frac{9}{2} from 8, 

we first write 8 as a fraction with denominator 2:

8=8. \frac{2}{2}= \frac{8.2}{2}= \frac{16}{2}

3.

Thus, 

8-4 \frac{1}{2}= \frac{16}{2}- \frac{9}{2}= \frac{16-9}{2}= \frac{7}{2}

4.

The simple fraction 7/2 is not an option, so we write it as a compound fraction as follows:

\frac{7}{2}= \frac{6+1}{2}= \frac{6}{2}+ \frac{1}{2}=3+ \frac{1}{2}=3\frac{1}{2}

(So write 7 as the sum of the largest multiple of 2, smaller than 7 + what is left. In our case these numbers are 6 and 1, then proceed as shown)

5. Answer: D
3 0
3 years ago
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Which equations have no solution? Check all that apply.
charle [14.2K]
Remember, |n|≥0 for all real numbers n

so

-|x|=0
times -1
|x|=0
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|x|=-15
false, can't have negative absolute value

-|x|=12
|x|=-12
false, no negative absolute value

-|-x|=9
|-x|=-9
false, no negative absolute value

-|-x|=-2
|-x|=2
x=2 or -2
true, has solutions



the ones that have no solutions are
|x|=-15
-|x|=12
-|-x|=9
5 0
4 years ago
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In triangle DEF, CG = (x + 5) units and DG = (3x - 2) units.
Snowcat [4.5K]

Answer:

34 units

Step-by-step explanation:

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6 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%284v%5E%7B-3%7D%20%29%5E3%2F3v%5E%7B-8%7D" id="TexFormula1" title="(4v^{-3} )^3/3v^{-8}" alt=
Svet_ta [14]

Answer:

=\frac{64}{3v}

Step-by-step explanation:

One is given the following equation:

\frac{(4v^-^3)^3}{3v^-^8}

Simplify the numerator, remember to raise every number inside the parenthesis to the exponent outside of the parenthesis. Bear in mind, an exponent raised to another exponent is equal to the exponent times the exponent it is raised to. Then simplify by multiplying the number by itself the number of times that the exponent indicates.

\frac{(4v^-^3)^3}{3v^-^8}

=\frac{4^3(v^-^3)^3}{3v^-^8}

=\frac{4^3v^-^9}{3v^-^8}

=\frac{64v^-^9}{3v^-^8}

Bring the variable (v) in the denominator (value under the fraction bar) to the numerator (value ontop of the fraction bar) by multiplying its exponent by (-1). This can be done simply because all operations in this equation are multiplication or division, remember, an exponent is another form of multiplication.

=\frac{64v^-^9}{3v^-^8}

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

Simplify, remember, multiplying two numbers with the same base that have an exponent is the same as adding the two exponents,

=\frac{(64v^-^9)(v^(^-^1^)^(^-^8^))}{3}

=\frac{(64v^-^9)(v^8)}{3}

=\frac{64v^-^9^+^8)}{3}

=\frac{64v^-^1}{3}

Now bring the variable to the denominator so that there are no negative exponents. Use a similar technique that was used to bring variables with exponents to the numerator.

=\frac{64v^-^1}{3}

=\frac{64}{3(v^(^-^1^)^(^-^1^))}

=\frac{64}{3v^1}

=\frac{64}{3v}

5 0
3 years ago
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