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Mazyrski [523]
3 years ago
8

Show that the roots of the equations

Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

Answer:

The roots are real and distinct.

Step-by-step explanation:

Given the following equation:

x^{2} + kx - k -2 =0

In this problem, a = 1, b = k and c = -k - 2

The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.

We get,

(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)

= k² + 4k + 8

Let's check:

At k = -2,

(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4




At k = 0,

(0)^2 + 4(0) + 8 = 8

At k = -100,

(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608

Therefore, we can conclude that for all values of k, the roots are real and distinct.

This has been a long way in answering this question, so it would be great if you could mark me as brainliest

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39. Find the value of the expression if x= -1 and y= 6.
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What is the value of y in the equation 6.4x + 2.8y = 44.4, when x = 3? y = 5 y = 6 y = 8 y = 9
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Answer:

9

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Let’s divide both sides of the equation with 6

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Let’s check by substituting the value of n to the given equation.

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