Question

Special Right Triangle

Answer 1

let ABC be a triangle

where,

• AB= 6cm
• BC= a
• AC = b

now

applying tan 30°

tan theta = perpendicular/base

=>tan 30° = 6/a

(since tan 30° = 1/√3)

=>1/√3 = 6/a

=> a = 6√3

applying cos Q for finding b

=>cos 60° = b/h

(since cos 60° = 1/2)

=>1/2= 6/b

=> b= 12