Answer:
C
Step-by-step explanation:
Use a factor<span> tree to express </span>60<span> as a </span>product<span> of prime </span>factors<span>. So the prime factorization of </span>60<span> is 2 × 2 × 3 × 5, which can be written as 2 </span>2<span> × 3 × 5.</span>
The data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9
<h3>When a measure is considered an outlier in a data-set?</h3>
A measure is considered an outlier in a data-set if it is very far from other measures, especially in these two cases:
- If the measure is considerably less than the second smallest value.
- If the measure is considerably more than the second highest value.
In this problem, he data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9.
The second highest value is 5.3, which is considerably less than 22.6, hence 22.6 is an outlier in the data-set.
More can be learned about statistical outliers at brainly.com/question/9264641
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Answer:
y = -7/2x+3
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
y = -7/2 x+b
Substitute the point into the equation
-4 = -7/2(2) +b
-4 = -7+b
Solving for b
-4+7 = -7+b+7
3 = b
The equation is y = -7/2x+3
Answer:
EB ≈ 1.563 in
Step-by-step explanation:
The diagonals of a rhombus divide the figure into four congruent right triangles. Angle DAB is bisected by EA, so angle EAB is 46°/2 = 23°. EB is the side opposite, so the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(EAB) = EB/AB
EB = (4 in)sin(23°) . . . . . . multiply by the hypotenuse
EB ≈ 1.563 in
