In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.
In exponential models there is a constant multiplicative rate of change.
The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.
We can test that using several pair of points.
The multiplicative rate of change is calcualted in this way:
[f(a) / f(b) ] / (a - b)
Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)
[12.5 / 5] / (2 - 1) = 2.5
[5 / 2] / (1 - 0) = 2.5
[2 / 0.8] / (0 - (-1) ) = 2.5
Then, do doubt, the answer is 2.5
Answer:
$576.80
Step-by-step explanation:
We have been given that Mr. Juárez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. The account earns 1% simple interest.
We are asked to find the total amount that Mr. Juárez will have in his account at the end of 3 years.
We will use simple interest formula to solve our given problem.
A = Final amount after t years,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
Let us convert 1% into decimal form,
1%=1/100=0.01
P=$560 and t=3
A=$560 (1+0.01(3))
A=$560 (1+0.03)
A= $560 (1.03)
A= $576.80
Therefore, Mr. Juárez will have $576. 80 in his account at the end of 3 years. Hope this helps!
Domain:-> ( (-infinity) ,4)
Range:-> ((-infinity),infinity)
increasing in (-2.8,1.4)
decrasing in ( (-infinity) ,-2.8 ) U (1.4, infinity)
Hope it helps...
Regards,
Leukonov/Olegion.
This is 16+85 i know it is becaout
Anyways the center will be (-9;6)