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erastovalidia [21]
3 years ago
13

Find the perimeter of the figure to the nearest hundredth.

Mathematics
2 answers:
jasenka [17]3 years ago
4 0

Answer:

The perimeter is 50.26 inches

Step-by-step explanation:

To find the circumference of the half-circle use \pid/2

C = 3.14(9 x 2)/2

C = 3.14(18)/2

C = 56.52/2

C = 28.26

P = 5 + 12 + 5 + 28.26

P = 50.26

Colt1911 [192]3 years ago
4 0
I don’t know sorrrryyy
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Roger is a florist who uses a triangular-shaped frame to arrange flower bouquets. He received an order to make a new bouquet suc
kvv77 [185]

The locations specified in the order regarding the shape will be B. longest side AC; smallest angle ∠C.

<h3>How to express the information?</h3>

From the information given, in the triangle where A = 59°, B is unknown, and C = 41°. Therefore, the value of B will be:

= 180° - (59° + 41°)

= 180° - 100°

= 80°

Therefore, the locations specified in the order regarding the shape will be longest side AC; smallest angle ∠C.

In conclusion, the correct option is B.

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4 0
2 years ago
I don’t get the problem and I’ve been trying to solve it
Black_prince [1.1K]
I'm gonna use c for circle, t for triangle, and s for square
c+t+s=13
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c+8=13
c=5
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circle is 5, triangle is 2, and square is 6
8 0
3 years ago
Given the two relations, which one is a function and why is the other one not a function
Reil [10]

Answer:

The other one (number2) is not a function, because if you plot those points in a graph and use the line rule it shows that more than one point is aligned in that line.

Step-by-step explanation:

4 0
3 years ago
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Jordan is a teacher and takes home 40 papers to grade over the weekend. He can grade at a rate of 6 papers per hour. How many pa
Mazyrski [523]

Answer:

10

Step-by-step explanation:

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6 0
3 years ago
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Find the equation of the line that is parallel to the given line and passes through the given point
Sati [7]

Answer:

\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}

Step-by-step explanation:

\text{Let}\ k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\==========================\\\\\text{We have}\ x+4y=-6.\\\text{Convert to the slope-intercept form:}\\\\x+4y=-6\qquad\text{subtract}\ x\ \text{from both sides}\\\\4y=-x-6\qquad\text{divide both sides by 4}\\\\y=\dfrac{-x}{4}-\dfrac{6}{4}\\\\y=-\dfrac{1}{4}x-\dfrac{3}{2}\to m_1=-\dfrac{1}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (9,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}\\\\x=9,\ y=-3\\\\-3=-\dfrac{1}{4}(9)+b\\\\-3=-\dfrac{9}{4}+b\qquad\text{add}\ \dfrac{9}{4}\ \text{to both sides}\\\\-\dfrac{12}{4}+\dfrac{9}{4}=b\to b=-\dfrac{3}{4}

\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (8,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}

x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1

\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4

5 0
4 years ago
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