Need help Now please on High School geometry a is altitude, if it doesn’t show on the picture

Mathematics

1 answer:

g100num [7]2 years ago

7 0

Answer:

1. Altitude

2. Median

3. Angle bisector

4. Perpendicular bisector

You might be interested in

In Arianna's math class, 1⁄6 of the students are also in her

Pani-rosa [81]

Answer:

0.166666667, to round up it is 0.17

Step-by-step explanation:

8 0

3 years ago

Ian wants to run 412 miles to get ready for his upcoming race.

tankabanditka [31]

Answer:

137.3 miles apart from each other

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

4vir4ik [10]

Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is tested if the mean length of jail time is still of 2.5 years, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is tested if it has increased, that is:

$H_1: \mu > 2.5$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of $z^{\ast} = 1.645$