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RideAnS [48]
2 years ago
9

Can someone help me with this?

Mathematics
1 answer:
Gekata [30.6K]2 years ago
5 0

An

Step-by-step explanation:

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Determine rather each equation is there not a equation. Write yes or no. if yes write equation in standard form. -2x-3=y
abruzzese [7]
I don't know about how to put that in standard form, but an equation has to have an equals sign... So, that would be an equation.
8 0
3 years ago
Evaluate<br> 5! 4!<br> ____<br> 7! 2!<br> Simple as much as possible
shepuryov [24]

The value of the factorial is 5!4!/7!2! = 2/7

<h3>What is factorial?</h3>

The product of all positive integers less than or equal to a given positive integer and denoted by that integer and an exclamation point.

Given:

5!4!/7!2!

= 5!* 4*3*2!/7*6*5!*2!

=4*3/7*6

=12/42

=4/14

=2/7

Hence, 5!4!/7!2! = 2/7.

Learn more about factorial here:

brainly.com/question/1357774

#SPJ1

8 0
2 years ago
Find the fourth roots of 256(cos 240° + i sin 240°).
Mashcka [7]

Answer with Step-by-step explanation:

We are given that

We have to find the fourth roots of given complex number.

(256)^{\frac{1}{4}}=(4^4)^{\frac{1}{4}}=4^^{\frac{1}{4}\times 4}=4

By using the formula

(a^b)^x=a^{bx}

\theta=240^{\circ}

\theta=\frac{240}{4}=60^{\circ}

Angle of rotation=\frac{360}{4}=90^{\circ}

Therefore, the four roots of given complex number are

4(cos 60^{\circ}+i sin60^{\circ})

4(cos150^{\circ}+i sin150^{\circ})

4(cos240^{\circ}+isin 240^{\circ})

4(cos330^{\circ}+i sin330^{\circ})

8 0
2 years ago
Help please (place and label the following numbers on the number line. Order them as best as you can.)
svet-max [94.6K]

Answer:

least to greatest in order: -5/2(-2.5), -2.5, -2, -1.75, -1, 1.75, 9/4(2.25)

8 0
3 years ago
I NEED HELP ASAP PLEASE
skad [1K]
A^2+b^2=c^2 so c^2=12^2+16^2 which then simplifies to c^2=144+256 then simplify that to c^2=400. After that take the square root of c^2 and the square root of 400. So your answer is c=20
5 0
3 years ago
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