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malfutka [58]
2 years ago
8

Please factorise x^2-7x-44

Mathematics
2 answers:
Naddika [18.5K]2 years ago
8 0

Answer:

(x+4)*(x-11)

Step-by-step explanation:

IgorC [24]2 years ago
5 0

Answer with explanation attached. Please check.

<em>Answered</em><em> by</em><em> Benjemin</em><em> </em>;)

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Pls help i have no idea how to do this <br> Find the Missing angles
Semenov [28]
To be honest I just know that #1 is 143 (I think)
8 0
3 years ago
Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho
Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

A_{g} = a.b

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

A_{s} = 540 m^{2}

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

A_{s} + A_{g} = (a+2x)*(b+2x)

540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}

557 m^{2} = ab + 2x(a + b) + 4x^{2}

557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0

540 - 69x - 4x^{2} = 0                              

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0
3 years ago
16(4 1/4) distrubuted
ss7ja [257]

Answer:

68

Step-by-step explanation:

Step 1: Convert fraction to improper

4 1/4 = 16/4 + 1/4 = 17/4

Step 2: Multiply 16 and 17/4

16(17/4) = 272/4 = 68

8 0
4 years ago
Rewrite the following expression as the sum if two addends. -0.03 - 1.809
kumpel [21]
The answer is -1.839
6 0
3 years ago
A concert earned $3,745 in ticket sales. One ticket to the concert cost $35.
damaskus [11]

Answer:

107 concert tickets were bought

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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