Answer:
6
Step-by-step explanation:
1. re-write the given system:
cx+3y=c-3; => y= -cx/3 +(c-3)/3
12x+cy=c; => y= -12x/c+c/12
2. according the condition the rule for the parallel graphs is:
-c/3= -12/c
3. to calculate the unknown 'c':
c²=36; ⇔c=±6
The quantity of water left in the tank as described in the task content is; 111 l 220ml.
<h3>What is the amount of water left in the tank?</h3>
The tank described in the task content initially contains 200 liters, in which case, 1 liter corresponds to 1000ml.
Hence, when 88l 580ml was used, the remaining quantity of water is; 200l - (88l 580ml) = 111 l 420ml.
And finally, since 200 ml leaked, the quantity of water left is; 111l 220ml.
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Answer:
The answer is C
Step-by-step explanation:
Took the test!
Answer:
the one on the left (the first one)
