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kaheart [24]
2 years ago
8

What are Operating Systems?

Computers and Technology
1 answer:
horrorfan [7]2 years ago
5 0

Answer:

the software that supports a computer's basic functions, such as scheduling tasks, executing applications, and controlling peripherals.

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February 1995, Kevin Mitnick was arrested. While on parole was he allowed to have a phone or computer?
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He was not allowed on a phone of computer after being arrested.

Explanation:

If you read about it he wasn't even allowed to work at 7-11 because of an electronic cash register.

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BRAINLIEST Which function will add a name to a list of baseball players in Python?
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Nina is trying to learn more about how computers work. She has repeatedly read that the motherboard is the "brain” of the comput
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Its

Processes the data on the computer .

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What special enterprise VPN supported by Cisco devices creates VPN tunnels between branch locations as needed rather than requir
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Dynamic Multipoint VPN

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2 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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