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2 years ago

What are Operating Systems?

Computers and Technology

1 answer:

horrorfan [7]2 years ago

5 0

Answer:

the software that supports a computer's basic functions, such as scheduling tasks, executing applications, and controlling peripherals.

You might be interested in

For what type of document would you use the landscape page orientation

inysia [295]

Hi there!

Many certificates (and usually most certificates) are in the landscape page orientation.

Hope this helps!

5 0

3 years ago

You want to make it possible for your smartphone to share its internet access wirelessly with your friends device which of the f

IrinaVladis [17]

Answer:WiFi or hotspots

Explanation:you will have to turn on your WiFi or hotspots on your smart phone and allow your friend to also turn his WiFi or hotspot after you will search for your WiFi and connect there he can use the internet

6 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

The assignment symbol can be combined with the arithmetic and concatenation operators to provide augmented assignment operations

uranmaximum [27]

Answer:

Yes, we can.

Explanation:

We can combine with the arithmetic and the concatenation operators to provide augmented assignment operations in the programming language Python.

This mean we can abbreviate expressions like n = n + 1

For example:

n += 10 this is equal to n = n + 10

n += "example" this is equal to n = n + "example"

In this example we have

variable = variable operator expression equal to variable operator = expression.

These arguments are often used in Python's loops.

3 0

3 years ago

Identify 3 distractions for young drivers and explain how you plan to minimize these distractions.

Rom4ik [11]

1 distraction is phones , texting and driving . They could have a system in their car which activated by a voice assistant who could do it al for them

4 0

3 years ago