Answer/Explanation:
Red/green colorblindness is a recessive, X-linked condition. That means that the affected gene is on the X chromosome, and that the phenotype will only be present if there is no "healthy" gene, which is dominant to the mutated gene.
For two unaffected people to have an affected son, the mother must be a carrier. Remember, females have two X chromosomes and males have one. So if a female is a carrier of the colorblindness mutation, she will have one copy of the mutation and one normal copy of the gene, and will therefore be unaffected.
The punnet square (attached) shows that all their female children would be unaffected (have the B gene), but 1:2 male children would be colorblind, as their only copy of the gene is mutated (b).
A. bundles of microtubules that separate to opposite poles of a cell - CENTRIOLESB. prepares protein-packed vesicles for release outside of the cell - VESICLESC. small storage sacs containing water, food, and waste - VACUOLESD. rough and smooth organelle that produces protein, steroids, and lipids - ENDOPLASMIC RETICULUME. tiny sacs at the end of the ER which contain protein - GOLGI COMPLEXF. chains of protein fibers that provide support and shape - CYTOSKELETONG. powerful enzymes used to process cellular activity - LYSOSOMES & PEROXISOMESH. whip-like structures on cells that are used for movement - FLAGELLAI. produces and assembles proteins - RIBOSOMES im not really sure but hope this help
Sorry my fried, i need more information to be able to help you.