BC/AC = EF/DF
10/20 = 20/DF
DF = 40
AB/BC = DE/EF
AB/10 = 36/20
so AB = 18
answer
AB = 18, DF = 40 (A. fist one is your answer)
Answer:
Initial value for Mrs. White is $600 more than Mrs. Brown.
The rate of change is same for both.
Step-by-step explanation:
Cost of car purchased by Mrs. White = $3,000
Rate at which she pays for the car = $300 per month
Cost of car purchased by Mrs. Brown = $2,400
Rate at which she pays for the car = $300 per month
So,
Initial value for Mrs. White was =$3,000
Initial values for Mrs. Brown was =$2,400
difference in initial values 
=$600
∴ Initial value for Mrs. White is $600 more than Mrs. Brown.
Rate of change of payment due for Mrs. White = $300 per month
Rate of change for payment due for Mrs. Brown = $300 per month
∴ The rate of change is same for both.
Since Mrs White had a higher initial value than Mrs Brown and both having same rates of change, therefore Mrs. White will take a longer time to pay the due.
A Canadian postal code looks like this:
K1A 3B1 .
So you have: letter - digit - letter - digit - letter - digit .
The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.
The total number of possibilities would be
(26·10·26) · (10·26·10) = 17,576,000 .
In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the
first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes.
One example is the code H0H 0H0 for Santa Claus ! Other special
codes are for sorting mail
bound for destinations outside Canada.
At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.
x+30=2x-70, x-70=30, x=100
180=(2(100)-70)+5y, 180=130+5y, 50=5y, y=10
Answer:
Step-by-step explanation:
The given sequence is 
The common difference is d=10-15=-5
The first term of this sequence is 
We want to find the 27th term in this sequence.
The 27th term is given by:
We substitute the values to get:
