The answer to this question is the second choice, jessica bought 1/4 more than derek
The side lengths of the pool 10 ft and 45 ft.
<u>SOLUTION:
</u>
Given, a rectangle swimming pool is 8 feet deep.
One side of the pool is 4.5 times longer than the other.
Let the length of pool be n feet, the width will be 4.5n feet
The amount of water needed for the swimming pool is 3600 cubic ft
We have to find the dimensions of the pool. Now, we know that,

On taking square root on both sides we get,

So, the width will be 
For this case we represent in the complex plane numbers of the form:
a + bi
Where,
a: real part
bi: imaginary part
We represent the real part on the x axis.
We represent the imaginary part in the y axis.
Therefore, for the following numbers we have:
-3 + 8i: quadrant 2
4i: on the vertical axis
6: on the horizontal axis
5-2i: quadrant 4