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lara [203]
2 years ago
12

4.

Mathematics
1 answer:
valkas [14]2 years ago
4 0

Answer: \boxed{y=\frac{4}{5}x-2}

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals, so as the slope of the given line is -5/4, the slope of the perpendicular line is 4/5.

Substituting into point-slope form,

y-6=\frac{4}{5}(x-10)\\\\y-6=\frac{4}{5}x-8\\\\\boxed{y=\frac{4}{5}x-2}

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Answer:

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Step-by-step explanation:

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<em>(</em><em> </em><em>y</em><em> </em><em>-</em><em> </em><em>y1</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>m</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>x1</em><em> </em><em>)</em>

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<em>[</em><em> </em><em>Ref</em><em>er to</em><em> the</em><em> attached</em><em> file</em><em> for</em><em> </em><em>furth</em><em>er</em><em> </em><em>process</em><em> </em><em>]</em>

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Read 2 more answers
By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i &lt; ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

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nignag [31]
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DaniilM [7]

Answer:

Step-by-step explanation:

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