Answer:
x < -2.5 and x > 1
Step-by-step explanation:
You solve an equation like this by adding the opposite of the constant to both sides of the equation.
... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b
... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0
... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V
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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.
Answer:
Step-by-step explanation:
The domain includes all x values, and here, it is [-2, 4].
This may be wrong but this is how id do it.
110.25 + 55.45 = 165.7
165.7 x 4.5 = 745.65 g of brown sugar
For the function f ( x ) = x² we have the new function f 1 ( x ) = 1/2 x².
f ( x ) = a · x²
- If |a| < 1 the graph is compressed vertically by a factor of a.
- If |a| > 1 the graph is stretched vertically by a factor of a.
Here: a = 1/2 < 1
Answer:
C. The graph will be compressed vertically.
