Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
Answer:
(x+1)^2 + (y-3)^2 = 16
Step-by-step explanation:
The equation of a circle is given by
(x-h)^2 + (y-k)^2 = r^2
Where (h,k) is the center and r is the radius
(x--1)^2 + (y-3)^2 = 4^2
(x+1)^2 + (y-3)^2 = 4^2
(x+1)^2 + (y-3)^2 = 16
Answer:
5,600 m^2
Step-by-step explanation:
a 1cm= 0.01m
560000(0.01)=5600
Ok, so if you want to convert 7/8 into a decimal, you just simply divide 7 into 8. Well that should be 0.875 because 7 ÷ 8 = 0.875 Hope that helped!!! :)
Miguel: 500 out of 750 students have part time jobs.
500 ÷ 250 = 2
750 ÷ 250 = 3
500:750 = 2:3
A) 200 out of 300 ⇒ 200/100 and 300/100 ⇒ 2:3
B) 700 out of 1100 ⇒ 700/100 and 1100/100 ⇒ 7:11
C) 800 out of 1200 ⇒ 800/400 and 1200/400 ⇒ 2:3
D) 9000 out of 1300 ⇒ 9000/100 and 1300/100 ⇒ 90:13
Among the choices, Choice B could represent Kureshi's Data because it is not proportional to the data of Miguel.
Choice D is not possible. You cannot have a result that is way beyond the scope of your population. It is impossible to get 9000 students out of only 1300 students.
