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Nesterboy [21]
2 years ago
8

8. What are the solutions to this system

Mathematics
1 answer:
AVprozaik [17]2 years ago
3 0

Answer:

Below in bold.

Step-by-step explanation:

3x + y = -1

2x + y=0

Subtract to eliminate y:

3x - 2x + y - y = -1 - 0

x = -1

So, substituting for x in the first equation;

3(-1) + y = -1

y - 3 = -1

y = 2.

The solution is the ordered pair (-1, 2).

The system is a pair of straight lines which intersect at the point (-1, 2).

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\left\{\begin{array}{ccc}x+y=-2\\2x-3y=-9\end{array}\right\\\\\text{multiply the first equation by 3}\\3(x+y)=3(-2)\qquad|\text{use distributive property}\\3x+3y=-6\\\\\underline{+\left\{\begin{array}{ccc}3x+3y=-6\\2x-3y=-9\end{array}\right}\qquad\text{add 3x+3y=-6 to 2x-3y=-9, and solve for x}\\.\qquad5x=-15\qquad|:5\\.\qquad x=-3\\\\\text{Substitute the value of x in the first equation (x+y=-2)}\\\\-3+y=-2\qquad|+3\\y=1\\\\\text{The solution for the system of equations is (-3, 1)}

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