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Ugo [173]
2 years ago
10

Find the area of the shaded regions below. Give your answer as a completely

Mathematics
1 answer:
Eddi Din [679]2 years ago
6 0

Answer:

\huge\boxed{A_R=18\pi\ cm^2}

Step-by-step explanation:

\dfrac{80^o}{360^o}=\dfrac{8}{36}=\dfrac{2}{9}

The shaded region is 2/9 of whole circle.

Calculate the area of a circle:

A=\pi r^2

r - radius

Substitute r=9cm

A_O=\pi\cdot9^2=81\pi(cm^2)

Calculate the area of the shaded regions:

A_R=\dfrac{2}{9}A_O\\\\A_R=\dfrac{2}{9}\cdot81\pi=2\cdot9\pi=18\pi(cm^2)

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Law of sines: 2.2 units 2.4 units 3.0 units 3.3 units
Arada [10]

Answer:

RS=2.4\ units  

Step-by-step explanation:

<em>The complete question is </em>

What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.

see the attached figure to better understand the problem

step 1

Find the measure of angle S

Applying the law of sines

\frac{QS}{sin(R)}=\frac{QR}{sin(S)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{2.4}{sin(S)}

Solve for sin(S)

sin(S)=\frac{sin(80^o)}{3.1}(2.4)

S=sin^{-1}[sin(80^o)}{3.1}(2.4)]

S=49.68^o

step 2

Find the measure of angle Q

Remember that the sum of the interior angles in any triangle mut b equal to 180 degrees

so

m\angle Q+m\angle R+m\angle S=180^o

substitute the given values

m\angle Q+80^o+49.68^o=180^o  

m\angle Q+129.68^o=180^o  

m\angle Q=180^o-129.68^o

m\angle Q=50.32^o

step 3

Find the length of segment RS

Applying the law of sines

\frac{QS}{sin(R)}=\frac{RS}{sin(Q)}

substitute the given values

\frac{3.1}{sin(80^o)}=\frac{RS}{sin(50.32^o)}

RS=\frac{3.1}{sin(80^o)}{sin(50.32^o)}  

RS=2.4\ units          

3 0
3 years ago
Suppose a car travels at a rate of 60 miles per hour for 3 hours. How many miles does the car travel?
nataly862011 [7]
Ok lol I was going to put 180 but if you got it than that’s fine.
3 0
2 years ago
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