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3 years ago

Hiiii could one of y’all help please. be 100% correct i’m having a hard time

Mathematics

1 answer:

ivanzaharov [21]3 years ago

4 0

Answer:

other

Step-by-step explanation:

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Simplify. 5x^3/(7x^3+x^4)

Mashutka [201]

Hello,

$\frac{5 x^{3} }{7 x^{3} + x^{4} } = \frac{5 x^{3} }{x^{3}(7+x) }=\frac{5} {7+x}$

Answer Almost A with parenthesis

5/(7+x)

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3 years ago

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3 years ago

-8 3/4 ÷ 2 1/6 how do I solve this <br><br>

alexira [117]

Answer:

-4 1/26

Step-by-step explanation:

You will want to Reduce the expression, if possible, by cancelling the common factors.

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3 years ago

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andriy [413]

Answer:

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Step-by-step explanation:

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3 years ago

Factor the following<br>(a²+b²)²-18(a²+b²)-88

navik [9.2K]

Answer:

$\rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)$

Step-by-step explanation:

we would like to factor the following:

$\rm\displaystyle ( {a}^{2} + {b}^{2} {)}^{2} - 18( {a}^{2} + {b}^{2} ) - 88$

let a²+b²=x

thus substitute:

$\rm\displaystyle x {}^{2} - 18x- 88$

rewrite the middle term as 4x-22x:

$\rm\displaystyle x^{2} + 4x - 22x - 88$

factor out x:

$\rm\displaystyle x( x^{} + 4)- 22x - 88$

factor out -22:

$\rm\displaystyle x( x^{} + 4)- 22(x + 4)$

group:

$\rm\displaystyle( x- 22)(x + 4)$

substitute back:

$\rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)$

and we are done!

6 0

3 years ago

Read 2 more answers