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Elanso [62]
3 years ago
14

One leg of a right triangle has a length of 5 m. The other lengths that are consecutive integers

Mathematics
2 answers:
malfutka [58]3 years ago
6 0

When they say the other 2 sides are consecutive integers then --> x = x + 1 , where 'x + 1' is the hypotenuse.

(x + 1)² = x² + 5²

x² + 2x + 1 = x² + 25 --> Both x² get cancelled.

2x + 1 = 25 ---> 2x = 24 ---> x = 12

The other leg is 12 m

The hypotenuse is 13 m hope this helped you.

SashulF [63]3 years ago
5 0

The two other points would be <u>5 m. and 3 m.</u>

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Macario is making 12 pounds of nut mixture with macadamia nuts and almonds. Macadamia nuts cost $9 per pound and almonds cost $5
Fynjy0 [20]

Marcario should use  4 pounds of macadamia nuts and 8 pounds of almonds.

Explanation

given

cost of macadamia nuts per pound=$9

cost of almond nuts per pound=$5.25

cost of the mixture per pound=$6.5

total pounds of the mixture to be made=12

let the pounds of macadamia nuts=x

pounds of almond nuts=y

total pounds of nuts=x+y=12

x+y=12(1)\\9x+5.25y=6.5(x+y)\\\\9x+5.25y=6.5*12\\9x+5.25y=78(2)

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5 0
2 years ago
Suppose that each observation in a random sample of 100 fatal bicycle accidents in 2015 was classified according to the day of t
liraira [26]

Answer:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0:  proportion of fatal bicycle accidents in 2015 was the same for all days of the week

against the claim

Ha:  proportion of fatal bicycle accidents in 2015 was not the same for all days of the week

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (ni - npi)²/ npi

which has an approximate chi square distribution with ( n-1)=7-1=  6 d.f

4) The critical region is χ² ≥ χ² (0.05)6 = 12.59

5) Calculations:

χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28

χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]

χ²= 1/14.28[8.1364]

χ²= 0.569= 0.57

6) Conclusion:

The calculated χ² =  0.57   does not fall in the critical region χ² ≥  12.59  so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.

b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week

6 0
2 years ago
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