Answer:
The largest rectangular space is 
Step-by-step explanation:
Given a 20m long wire fence, implies that the perimeter of the fence has been given, because Perimeter can be defined as the length of the boundary of a figure (in this case, a rectangle)
So, from the formula: Perimeter = 2 (L + B) = 
We have that L + B = 
The possible values of L and B are:
(L, B) = (9, 1), (8, 2), (7, 3) and (6, 4).
The areas of the rectangle that will be formed using these values are respectively;
,
,
and
, the largest area of which is the last which corresponds to the values (6, 4).
The largest rectangular space that the gardener can enclose is therefore 
Answer:
Cylinder
(with radius of 4 units and height of 4 units)
Step-by-step explanation:
First, determine the shape of the 2D figure.
Point B is above point A, and point C is above point D.
Point A and B, and points C and D are on the same horizontal line.
Points A and B both have an x-value of zero.
Points C and D both have an x-value of 4.
Therefore, the width of the shape is 4 units
Points A and D have an y-value of zero.
Points B and C have an y-values of 4.
Therefore, the height of the shape is 4 units.
Therefore, the shape of the 2d figure is a square with side length of 4 unit. (See first attached image).
If the square is rotated above the y-axis, it creates a cylinder with a radius of 4 units and a height of 4 units. (See second attached image).
Answer:
Step-by-step explanation:
We can plug this into a formula and get

the .9075 comes from 1 - the depreciation value of 9.25% which converts to .0925 in decimal form.
? is what we are trying to solve for.
We can divide both sides by 19,700 and we get

so ? is about 13.
451.76 and <span>451.7576 these two</span>
The answer would be: There were 2 chefs and 13 customers.