Question

Carlos cycles for 2 hours at a fast speed, then cycles for 3 more hours at a speed 10 km/h slower than this. If the entire distance travelled is 90 km, find Carlos’ speed in the first two hours of travel.

Answer 1

Answer:

f=24km/h

Step-by-step explanation:

Alright, here's what we know.

He travels 2 hours at a fast speed, lets call that speed f km/h

He then travels 3 hours at (f-10) km/h

In these 5 hours, he travels 90km

So we have the formula velocity = distance/time. If you don't know where that formula comes from, let me know and I'll explain.

So we have:

$v=\frac{d}{t}$

d and t are given to us as 90 and 5 respectively

v is going to be his average speed, so we take 2 times the fast speed plus 3 times the slower speed and divide it by 5. This gives us the average speed he traveled over the 5 hours.

$\frac{2f+3(f-10)}{5} =\frac{90}{5}$

2f+3f−30=90  by cancelling the 5's in the denominator and expanding 3(f−10)

5f=120

f=24km/h

So his faster speed is 24 km/h. Let me know if this solution did not make sense to you at any point.