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Pavlova-9 [17]
3 years ago
9

Which diagram could be used to prove (triangle) ACB ~ (triangle) DEC using similarity transformations?

Mathematics
1 answer:
solong [7]3 years ago
5 0

Answer:

C because a b and d do not show any similaritys

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If a dart board was thrown randomly at the dartboard shown below, what is the probability that it will land in the bull’s-eye? T
vampirchik [111]

Answer:

Correct option: C -> 2%

Step-by-step explanation:

To find this probability we just need to divide the area of the bull's-eye circle by the total area of the outer circle.

The area of a circle is given by the equation:

area = \pi * radius^2

The outer radius is 14 cm, so:

outer\ area = \pi * 14^2 = 196\pi\ cm^2

The inner radius is 2 cm, so:

inner\ area = \pi * 2^2 = 4\pi\ cm^2

So the probability is:

inner\ area / outer\ area = 4\pi / 196\pi = 0.02 = 2\%

Correct option: C

3 0
3 years ago
Maria exercises for 2 1/7 hours every Saturday. She runs for 1/3 of the time that she exercises. How much time does she spend ru
mario62 [17]
2\frac{1}{7}*\frac{1}{3}=\frac{15}{7}*\frac{1}{3}=\frac{15*1}{7*3}=\frac{15}{21}=\frac{5}{7}
\frac{5}{7}*60=\frac{5*60}{7}=\frac{350}{7}=42,(857142)min\approx 42.86min
8 0
4 years ago
What is the product of x(x 1)? 2x x x2 2x 2x2 x x2 x
nalin [4]
X(x + 1) = x^2 + x..
8 0
3 years ago
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Image is attached <br> Find x and y of 2 similar polygons
Lapatulllka [165]

Answer:

11

Step-by-step explanation:

10/15=6/x-2

then solve for x

x=11

5 0
2 years ago
A car moving at a constant speed passed a timing device at t = 0. After 8 seconds, the car has traveled 936 ft. Write a linear f
Ahat [919]

Answer:

Buenos días;

1) La ecuación de la velocidad en un movimiento uniformemente acelerado (M.U.A) es:

V=V₀+at.

V=30 m/s-2 m/s².t

Ahora elimina las unidades (m/s, m/s₂), y tendrás la ecuación de la velocidad en función del tiempo.  

V(t)=30-2t.

Sol: la ecuación de la velocidad en función del tiempo es : V(t)=30-2t.

2) La ecuación de la posición en función del tiempo en un M.U.A  es:

X=X₀+V₀.t+(1/2).a.t²

X=0+30 m/s.t+(1/2).(-2 m/s²).t²

Eliminas las unidades, y tendrás la ecuación de la posición en función del tiempo.

X(t)=30.t-t².

Sol: la ecuación de la posición en función del tiempo es: X(t):30t-t²

Un saludo.

Step-by-step explanatio:g

5 0
3 years ago
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