Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
Answer:
428 is equal to 428
Step-by-step explanation:
300 + 120 = 420 + 8 = 428
Fraction -> Decimal
4/5 = 0.8
1/8 = 0.125
Decimal -> Percent
0.22 * 100% = 22%
0.47 * 100% = 47%
Percent -> Fraction
34% / 100 = 0.34 = 17/50
25% / 100 = 0.25 = 1/4
Fraction -> Percent
1/3 = 0.33... * 100% = 33.3%
2/5 = 0.4 * 100% = 40%
Decimal -> Fraction
0.65 = 65/100 = 13/20
0.4 = 4/10 = 2/5
Percent -> Decimal
81% / 100 = 0.81
4% / 100 = 0.04
Best of Luck!
ITS C - Factor 6 out of the variable terms
Answer: Printer A can print (576/48) 12 pages per minute. Printer B can print (1104/48) 23 pages per minute
Step-by-step explanation:
