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Natalija [7]
3 years ago
13

What is the difference (2 x - 3) - (x - 1)? x minus 4 x minus 2 x + 2 x + 4

Mathematics
2 answers:
Crank3 years ago
6 0

Answer:

Step-by-step explanation:

It may help you to rewrite this problem in columns:

 2x - 3

-(  x - 1)

------------

   x - 2 (answer) ("x minus 2")

kupik [55]3 years ago
5 0

Answer:

x - 2

Step-by-step explanation:

2x - x = x

-3 - -1 = -2

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Write and solve an equation to find the value of x and the missing angle measures.
Oksana_A [137]

Answer:

Step-by-step explanation:

1). Since, both the angles are vertically opposite angles,

  Measure of both the angles will be same.

  6x = 30

   x = 5

2). Since, both the angles are the linear pair of angles,

   (4 + 5x)° + (x + 2)° = 180°

    6x + 6 = 180

    6x = 180 - 6

    x = \frac{174}{6}

    x = 29

    Therefore, (4 + 5x)° = 4 + 5(29)

                                     = 149°

    And (x + 2)° = (29 + 2)

                        = 31°

3). Since, both the angles are linear pair of angles,

    5x° + (3x + 12)° = 180°

    8x + 12 = 180

    8x = 180 - 12

    x = \frac{168}{8}

    x = 21

    Therefore, 5x° = 5(21)

                             = 105°

    (3x + 12)° = 3(21) + 12

                    = 75°

8 0
3 years ago
What is the y-intercept of the graph of the linear function?
ELEN [110]

Answer:

-4,5

Step-by-step explanation:

3 0
3 years ago
Use the model to write the equation that represents the problem.
ella [17]

Answer:

I wanna say 13 1/2 is the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
Que porcientos es 200 de 600
kumpel [21]
   
\displaystyle  \\ 
 \frac{200}{600} =   \frac{2}{6} =  \frac{1}{3} = 0,(3) =  \frac{33,(3)}{100} = \boxed{33,(3)\%}



8 0
3 years ago
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