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Damm [24]
2 years ago
12

The midpoint of overline AB is M(7,-7) . If the coordinates of A are (8, - 6) , what are the coordinates of B?

Mathematics
1 answer:
dexar [7]2 years ago
5 0

Measure the distance between the two end points, and divide the result by 2. This distance from either end is the midpoint of that line. Alternatively, add the two x coordinates of the endpoints and divide by 2. Do the same for the y coordinates.

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If T(x, y) = (x + 5, y + 6) and Pris the image of P, what is the rule for the translation in which P is the image of P'? T(x, y)
xxTIMURxx [149]

Answer:

The translation is;

T(x,y)=(x-5,y-6)

Explanation:

Given the translation rule;

T(x,y)=(x+5,y+6)

when P' is the image of P.

For the inverse, when P is the image of P', the Translation rule would become;

\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}

The translation is;

T(x,y)=(x-5,y-6)

3 0
1 year ago
Please help I’ll give you points and mark you brainliest
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ANSWER:

i think it’s c
5 0
2 years ago
What is the inverse of cube root x/3 +1
Ostrovityanka [42]

Answer:

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

Step-by-step explanation:

We want to find the inverse of

y = \sqrt[3]{ \frac{x}{3} + 1}

We interchange x and y to get:

x= \sqrt[3]{ \frac{y}{3} + 1}

We solve for y;

{x}^{2}  =  \frac{y}{3}  + 1

Multiply through by 3

3 {x}^{2}  = y + 3

Subtract 1 from both sides:

y = 3 {x}^{2}  - 3

Therefore the inverse is

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

8 0
3 years ago
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John is 6 years old and mary is 3. 
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