Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Step-by-step explanation:
B = area of the base
= 9×4 = 36 square inches
P= perimeter of the base
= 2(9+4)
=2×13= 26 inches
H =distance between the bases
= 16 inches
SA= 2B+PH
= 2(36)+ 26× 16
= 72+416 = 488 square inches
They are mad as easy try it on your own your answer is suppose to be 80
Change the mixed numbers into improper fractions:
5/3 X 9/2
Reduce - the 3 and 9 can be simplified
5/1 X 3/2
multiple numerators and denominators
15/2
Not sure how you need the answer - i would change it into a mixed number
7 1/2
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