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Vesnalui [34]
3 years ago
13

Quiz

Mathematics
1 answer:
Harman [31]3 years ago
3 0

Answer:

h=-6 k=-30

Step-by-step explanation:

y=x^2+12x+6

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}

a=1,\:b=12,\:c=6

x_v=-\frac{b}{2a}

x_v=-\frac{12}{2\cdot \:1}\\

x_v=-6\\

\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)

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Find the domain and range of the function f(x) = 3x^2 - 5.Also find f(-3) and the numbers which are associated with the number 4
Delicious77 [7]

Domain:


This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: D = \mathbb{R}


Range:


A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like [a,\infty). To find the minimum, let's start with the "standard" parabola y=x^2, and transform it to the one of this exercise. y=x^2 has minimum 0, and thus its range is [0,\infty). When you multiply it times three, its shape narrows, but the range wont change: [0,\infty) \to [3\cdot 0,3\cdot \infty) = [0,\infty). Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have [0,\infty) \to [0-5,\infty-5) = [-5,\infty)


Image of -3:


To compute f(-3), simply plug x=-3 in the formula:


f(-3) = 3(-3)^2-5 = 3\cdot 9 - 5 = 27-5 = 22


Numbers associated with 43:


We want to see which x value we must choose to get a y value of 43. So, the equation is


y = 3x^2-5 \to 43 = 3x^2-5 \iff 48 = 3x^2 \iff 16 = x^2 \iff x = \pm\sqrt{16} = \pm4

4 0
4 years ago
WILL GIVE BRAINLIEST!!
djverab [1.8K]

Answer:

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4 years ago
Please state the function for the corresponding data set
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Given:
x: [1      2         3        4      5    6        7]
y: [9  9.5  10.25  11.25  12.5  14  15.75]

Let the function which models the data be
y(x) = ax² + bx + c

Apply the function to the first three data points
  a +   b + c = 9           .(1)
4a + 2b + c = 9.5        (2)
9a + 3b + c = 10.25    (3)

Subtract (1) from (2).
3a + b = 0.5
or
b = 0.5 - 3a               (4)
Subtract (1) from (3).
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Substitute (4) into (5).
8a + 2(0.5 - 3a) = 1.25
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From (4),
b = 0.5-3*0.125 = 0.125
From (1),
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The function is
y = 8.75 + 0.125x + 0.125x²

Check that the function works for x=4,5,6,7.
From the calculator, obtain
y(4) = 11.25  Correct
y(5) = 12.5  Correct
y(6) = 14      Correct
y(7) = 15.75 Correct

The graph of the function is shown below.

Answer:  y = 8.75 + 0.125x + 0.125x²

5 0
4 years ago
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mafiozo [28]

Answer:

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Step-by-step explanation:

We can see that the face of the given rectangular prism shows the width 4 and the height of 6. If we cut the figure at any point along the length 20, such that the cross section is parallel to the face, the cross section, which occurs at x length, will always have the same dimensions, that are 4 and 6.

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Answer:

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6 0
4 years ago
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