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3 years ago

Quiz

Mathematics

1 answer:

Harman [31]3 years ago

3 0

Answer:

h=-6 k=-30

Step-by-step explanation:

$y=x^2+12x+6$

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}$

$a=1,\:b=12,\:c=6$

$x_v=-\frac{b}{2a}$

$x_v=-\frac{12}{2\cdot \:1}\\$

$x_v=-6\\$

$\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)$

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B(1)= -12

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Given:

$b(1)=-12$

$b(n)=b(n-1)\cdot 4$

To find:

The third term of the sequence.

Solution:

We have,

$b(n)=b(n-1)\cdot 4$

For n=2, we get

$b(2)=b(2-1)\cdot 4$

$b(2)=b(1)\cdot 4$

$b(2)=-12\cdot 4$ $[\because b(1)=-12]$

$b(2)=-48$

For n=3, we get

$b(3)=b(3-1)\cdot 4$

$b(3)=b(2)\cdot 4$

$b(3)=-48\cdot 4$ $[\because b(2)=-48]$

$b(3)=-192$

Therefore, the 3rd term of the sequence is -192.

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2 years ago

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3 years ago

Read 2 more answers

How do I verify this identity? I know you should write sin2a as sin(a+a).

Kisachek [45]

SOLUTION

Given the question in the image, the following are the solution steps to verify the identity

STEP 1: Write the given identity

$\sin 2\alpha=2\sin \alpha\cos \alpha$

STEP 2: Verify the identity

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1 year ago

Which expression correctly shows 2x³y - 2y factored completely?

OverLord2011 [107]

Answer:

$2y(x-1)(x^2+x+1)$

Step-by-step explanation:

$~~~2x^3y-2y\\\\=2y(x^3-1)\\\\=2y(x-1)(x^2+x+1)~~~~~~~~~~;[a^3-b^3 = (a-b)(a^2 +ab+b^2)]$

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1 year ago

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Marrrta [24]

Answer:

x = 14

Step-by-step explanation:

So because the sides are equal, that means that the angles are equal.

5x = 3x + 28

Step 1.) Subtract 3x from 5x which leaves you with 2x.

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Step 2.) Divide 28 by 2, to get the variable on its own. This leaves you with 14

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2 years ago