Question

Quiz

Answer 1

Answer:

h=-6 k=-30

Step-by-step explanation:

$y=x^2+12x+6$

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}$

$a=1,\:b=12,\:c=6$

$x_v=-\frac{b}{2a}$

$x_v=-\frac{12}{2\cdot \:1}$

$x_v=-6$

$\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)$