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Vesnalui [34]
3 years ago
13

Quiz

Mathematics
1 answer:
Harman [31]3 years ago
3 0

Answer:

h=-6 k=-30

Step-by-step explanation:

y=x^2+12x+6

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}

a=1,\:b=12,\:c=6

x_v=-\frac{b}{2a}

x_v=-\frac{12}{2\cdot \:1}\\

x_v=-6\\

\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)

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Read 2 more answers
PLEASE HELP
lions [1.4K]
This question is easy if you think about it. First get the area of the rectangular part of the shape and then find area of the two semi-circles then add them together.

First, let's solve for the rectangle because it's easier.

Area for finding a rectangle A = w * l

A = 23 * 37
A = 851

Now for the semi-circle. First use the equation for finding the area of a circle which is A = Pi * r^2. We'll use 3.14 for Pi.

We know the diameter is 23. And to get the radius we just half it because the radius is half of the diameter.

23 / 2 = 11.5

A = 3.14 * 11.5^2
A = 3.14 * <span>132.25
</span>A = <span>415.265
</span>
Now we have the total area for both semi-circles. Because if we half 415.265 then add the other semi-circle's area it will be the same and adding them up will result in 415.265.

Now add up 851 and 415.265.

851 + 415.265 = <span>1266.265</span>

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3 years ago
Prove that the product of the second and third numbers out of four consecutive whole numbers is two greater than the product of
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Let the four consecutive numbers be x,x+1,x+2,x+3.

Now the product of second and third number=(x+1)(x+2)=x²+3x+2=k

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A.T.Q

product of second and third number= product of first and fourth number+2

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