To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.
The work done on moving the object is 27ft*lbs
<h3>Work done in moving the object from point A to point B</h3>
To find the work done on this object, let's find the net force on the object.
Data;
- force = 4lb
- direction = 4, -2
- displacement = 7ft
- direction = (0, 4) to (5,1)
The unit vector of the force is
The net force acting on the object is
The displacement on the object is 7ft through (0,4) to (5, -1)
The unit vector on displacement is
The net displacement will be
The work done will be F.d
The work done on moving the object is 27ft*lbs
Learn more on work done on an object here;
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Answer:
d + (d • 0.08)
d(1+0.08)
Let’s say that d is equal to 50.
50 + (50 • 0.08) = 54
50(1+0.08) = 54
Hope this helps!
Answer:
4x+7z
Step-by-step explanation:
4x + 2z + z +4z is the expression
The simplified expression is just the terms combined
so,
4x + 2z+1z+4z
4x+3z+4z
4x+7z
Answer:
D
F
Step-by-step explanation:
Parallel lines are lines of equal distance apart (equidistant), that are on the same plane but they never meet
Perpendicular lines meet thus they are not parallel lines
Also, lines that intersect , meet, thus they are not parallel lines
Answer: (x-2)^2+(y+3)^2 = 9Side notes
1) This circle has a center of (2,-3)
2) The radius of this circle is 3
3) The graph is shown in the attached image
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Work Shown:
x^2-4x+y^2+6y+4=0
x^2-4x+y^2+6y+4-4=0-4
x^2-4x+y^2+6y = -4
x^2-4x+4+y^2+6y = -4+4 ... see note 1 below
(x^2-4x+4)+y^2+6y = 0
(x-2)^2+y^2+6y = 0
(x-2)^2+y^2+6y+9 = 0+9 ... see note 2 below
(x-2)^2+(y^2+6y+9) = 9
(x-2)^2+(y+3)^2 = 9note 1: I'm adding 4 to both sides to complete the square for the x terms. You do this by first taking half of the x (not x^2) coefficient which in this case is -4. So take half of -4 to get -2. Then square this result to get 4
note 2: Like with note 1, I'm completing the square. What's different this time is that this is for the y terms now. The y coefficient is 6. Half of this is 3. Square 3 to get 9. So this is why we add 9 to both sides.
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So
the equation in standard form is (x-2)^2+(y+3)^2 = 9Note how
(x-2)^2+(y+3)^2 = 9
is equivalent to
(x-2)^2+(y-(-3))^2 = 3^2
So that second equation listed above is in the form (x-h)^2+(y-k)^2 = r^2
where
h = 2
k = -3
r = 3
making the center to be (h,k) = (2,-3) and the radius to be r = 3
The graph is attached.
