Y=(5-x)/2 thats the answer
Answer: 5
Step-by-step explanation:

Answer:
87.5%
Step-by-step explanation:
The area of the entire rectangle is 8 by 6,
8x6=48 so the area is 48 units^2.
The area of the triangle is A=1/2bh
A=1/2(2)(6)
A=1(6)
A=6 units^2
6/48=0.125
0.125=12.5%
You need to find the percent it will not land in the triangle, so subtract 12.5 from 100.
100-12.5=87.5
There is an 87.5% chance it will not land in the triangle
First we need to convert the given equation to standard form, only then we can find the center and radius of the circle.
![x^{2} + y^{2} +18x+14y+105=0 \\ \\ x^{2} +18x+ y^{2}+14y=-105 \\ \\ x^{2} +2(x)(9)+ y^{2}+2(y)(7)=-105 \\ \\ x^{2} +2(x)(9)+ 9^{2} + [y^{2}+2(y)(7)+7^{2}] =-105+9^{2}+7^{2} \\ \\ (x+9)^{2}+ (y+7)^{2}=25 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20%2B18x%2B14y%2B105%3D0%20%5C%5C%20%20%5C%5C%20%0A%20x%5E%7B2%7D%20%2B18x%2B%20y%5E%7B2%7D%2B14y%3D-105%20%5C%5C%20%20%5C%5C%20%0A%20x%5E%7B2%7D%20%2B2%28x%29%289%29%2B%20y%5E%7B2%7D%2B2%28y%29%287%29%3D-105%20%5C%5C%20%20%5C%5C%20%0Ax%5E%7B2%7D%20%2B2%28x%29%289%29%2B%209%5E%7B2%7D%20%2B%20%5By%5E%7B2%7D%2B2%28y%29%287%29%2B7%5E%7B2%7D%5D%20%20%3D-105%2B9%5E%7B2%7D%2B7%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%0A%20%28x%2B9%29%5E%7B2%7D%2B%20%28y%2B7%29%5E%7B2%7D%3D25%20%20%0A%20%20)
The standard equation of circle is:

with center (a,b) and radius = r
Comparing our equation to above equation, we can write
Center of circle is (-9, -7) and radius of the given circle is 5
Answer:
x = t
y = -t
z = (17-6t)/5
Step-by-step explanation:
First we will write down Equation 1 and Equation 2
4x-2y+5z = 17------(1)
x + y = 0--------(2)
Since we are asked to express our answer in terms of the parameter t so lets suppose x = t and y = -t
Now substitute the value of x and y in equation (1) we get
4(t) -2(-t) +5z = 17
6t + 5z = 17
5z = 17 -6t
z = (17-6t)/5
hence we get the following answer
x = t
y = -t
z= (17-6t)/5
we can also verify our answer by substituting the values of x ,y and z in any of the two equations above, for example lets substitute these values in equation 1
4(t) -2(-t) + 5((17-6t)/5)) = 17
6t + 17 -6t = 17
6t -6t = 17 -17
0 = 0