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1 year ago

Please help I’m in the middle of an exam!!

Mathematics

1 answer:

Tpy6a [65]1 year ago

6 0

Answer:

value x proves this parallelogram is a rhombus.

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You look over the songs in a jukebox and determine that you like 1414 of the 5252 songs. (a) What is the probability that you l

enyata [817]

Answer:

Step-by-step explanation:

given that you look over the songs in a jukebox and determine that you like 14 of the 52 songs

Here each song is independent of the other song

i.e. p = Probability that you like any song = $\frac{14}{52} =0.2692$

q = Prob you do not like = 1-0.2692 = 0.7308

a) the probability that you like the next four songs that are played

= $0.2692^4\\=0.00525$

b) the probability that you do not like the next four songs that are played

= $0.7308^4\\=0.2852$

3 0

2 years ago

After you find the solution, how would you check to make sure your answer is correct?

krek1111 [17]

Answer:

Plug in your variables value.

Step-by-step explanation:

For your case, plug in -6 into the y slot

12(5+2y)= -(6-9y) +4y

12(5+2x-6)= -(6-9x-6)+4y see if that works!

5 0

2 years ago

Read 2 more answers

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

Anyone help with these 2 question?

ICE Princess25 [194]

Step-by-step explanation:

1.√2×(-2√9)×(-√2)

= -2×(-2×3)

=12 option a

2. √5×√15×√75

= √5×(√3√5)×(5√3)

= 5×3×5

=75 option b

8 0

2 years ago

What is an equation in point-slope form of the line that passes through the point (4, −1) and has slope 6?

AveGali [126]

Answer: A

Step-by-step explanation:

See attached picture

7 0

3 years ago