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3 years ago

Exterior Angles of A Triangle

Mathematics

1 answer:

gladu [14]3 years ago

7 0

The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.

Try doing this for the rest of them

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On a graph of the area of a square vs. its perimeter, a few points are plotted.

k0ka [10]

Answer:

Step-by-step explanation:

8 0

3 years ago

x+4y=17 and -x-6y=-23 what's the x and y I really badly need this I need this so I can play at my basketball game tommorw and I

loris [4]

Answer:

x = 5
y = 3

Solution:

=> x + 4y = 17

-x - 6y = -23

=> -2y = -6
=> y = 3

Now, let's substitute the value of y into the first equation.

x + 4y = 17
=> x + 4(3) = 17
=> x + 12 = 17
=> x = 5

Let's check our answer to make sure it is correct.

Check:

-x - 6y = -23
=> -(5) - 6(3) = -23
=> -5 - 18 = -23
=> -23 = -23

Hence, this is proven correct.

Hoped this helped.

$BrainiacUser1357$

7 0

2 years ago

Find the height of a cone with a diameter of 12 m whose volume is 226 m^3.

lozanna [386]

5m the answer because the height of the cone

4 0

3 years ago

Read 2 more answers

Using polygon STUVW what is m angle U ?

bija089 [108]

Answer:

The m∠ U is 72°.

Step-by-step explanation:

Given:

$\angle S = 90\\\angle T = 2x\\\angle U = x\\\angle V = 2x\\\angle W = 90\\$

To find :

$\angle U = x = ?$

Solution:

The sum of the measures of the interior angles of a polygon with 'n' sides is given as

$\textrm{sum of the measures of angle of a polygon with 'n' sides} = (n - 1)\times 180$

Here we have n = 5 on substituting the values we get

$\angle S +\angle T + \angle U +\angle V + \angle W = (5 -2)\times 180\\90 + 2x + x + 2x + 90 = 3\times 180\\5x + 180 = 540\\5x = 540-180\\5x = 360\\x = \frac{360}{5}\\x = 72$

Therefore,

m∠ U is 72°.

4 0

3 years ago

A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,

tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0

4 years ago