Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach? well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.
if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.
the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.
Vertical symmetry because you can cut a square in half vertically and the two parts be exactly the same. Horizontal symmetry because you can cut a square in half horizontally and the two parts be exactly the same. Diagonal symmetry because you can cut the square from corner to corner and the two parts look exactly the same. Rotational symmetry because you can rotate the square and it still look exactly the same. So a square has all of those symmetries. I hope this helped!
Label each nut with a variable, c = cashews, p = peanuts.....
for a 10-pound mix, you will need c + p = 10
the price for 10-pounds would become 3.29 x 10 = 32.90
You will need an unknown amount of cashews at 5.60/lb and an unknown amount of peanuts at 2.30/lbs to get your full 10 pounds valued at 32.90
5.60c + 2.30p = 32.90
Now you 2 have a system of 2 equations and 2 unknowns
c + p = 105.6c + 2.3p = 32.9utilize substitution to solve:p = 10-c
5.6 c + 2.3 (10-c) = 32.9
solve for c then substitute back into c + p = 10 to solve for P
Hope this helps!
Answer:
true is the answer not hard question
Complete Question:
A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?
Answer:
A) 0.61351
Step-by-step explanation:
Sample proportion = 0.4
Sample population = 200
A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion
Statistically:
P(0.4-0.03<p<0.4+0.03)
P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200
P[-0.03/0.0346410 < z < 0.03/0.0346410
P(−0.866025 < z < 0.866025)
P(z < - 0.8660) - P(z < 0.8660)
0.80675 - 0.19325
= 0.61351
B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion
Statistically:
P(0.4-0.08<p<0.4+0.08)
P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200
P[-0.08/0.0346410 < z < 0.08/0.0346410
P(−2.3094 < z < 2.3094)
P(z < -2.3094 ) - P(z < 2.3094)
0.98954 - 0.010461
= 0.97908
