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3 years ago

Please help me? step by step:) ty

Mathematics

1 answer:

Illusion [34]3 years ago

4 0

Answer:

multiply 5 x 4 = 20

multiply the dimensions of the lighter square

after all the multiplying you subtract your answers and you should get the VERY final answer

*don't add because it's area; just multiply

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Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

2 years ago

Sandra is 30 years old and deciding which investment she would like to make. She has $2,500 to invest.

rusak2 [61]

12.596 I hope this helps!!

8 0

2 years ago

How do you solve this system: y= -3/2x, and 3x+2y=-4 by substitution?

Soloha48 [4]

Download Photomath it will answer it with step by step work

4 0

3 years ago

Read 2 more answers

-3/2(x - 5) = -12.

Alchen [17]

Answer:

x=13

Step-by-step explanation:

6 0

3 years ago

. Approximate each of the following logarithms to four decimal places. Use the LOG key on your calculator rather than logarithm

Free_Kalibri [48]

Answer:

$log_2(6)=2.584$

Step-by-step explanation:

Here the logarithm has base 2

$log_2(3^2)=log_2(6)$

Let

$log_2(6)=x$

$log_ya=x\\\Rightarrow y^x=a$

$\\\Rightarrow 2^x=6$

Now, take logarithm to the base 10

$log 2^x=log6\\\Rightarrow xlog2=log6\\\Rightarrow x=\frac{log6}{log2}\\\Rightarrow x=2.584$

So, $log_2(6)=2.584$

5 0

3 years ago