All categories

3 years ago

Please help me answer this in variable terms and constant terms -5.6x + 7 + 24y - 9

Mathematics

1 answer:

Olin [163]3 years ago

6 0

Answer:

Variable terms:

x and y

Constant terms:

7 and -9

Coefficient terms:

-5.6 and 24

You might be interested in

The value of x is: A. 40 B. 20 C. 13

tangare [24]

Hey there!

Write a proportion. 8/5=32/x. Cross multiply. You get 8x=160. You have to isolate x, so divide each side by 8. X=20. Since x is by itself, you have your answer. The answer is B. Another way to do this is to see how much it takes to get from 8 to 32. You would multiply by 4. So multiply 5 by 4 to get 20.

I hope this helps!

6 0

3 years ago

-5/7÷30/-4 What is the full explanation on how to work out this problem?

jasenka [17]

Answer:

1/168

Step-by-step explanation:

First, solve for the numerator.

-5/7÷30

-5/7÷30/1

(use keep, change flip)

-5/7x1/30=-5/210

-5/210=-1/42

Now use keep change flip again

-1/42÷-4/1

-1/42*-1/4=1/168

8 0

3 years ago

The dot plots below show the test scores of some mathematics students and some science students: Two dot plots are shown one bel

ohaa [14]

Answer:

Science students

Step-by-step explanation:

MATHEMATICS :

Plot interval = 30 to 50

MEAN :

(34*2) + (40*2) + (32*1) + (33*1) + (35*1) + (37*1) + (39*1) = 324

Sample size, n = (2 + 2 + 1 + 1 + 1 + 1 + 1) = 9

Mean = 324 / 9 = 36

BOTTOM :

SCIENCE :

MEAN : (43*2)+(46*2)+(49*2)+(41*1)+(42*1)+(47*1) =

406

SAMPLE SIZE = (2 + 2 + 2 + 1 +1 +1) = 9

406 / 9 = 45.111

8 0

2 years ago

On Martin's first stroke, his golf ball traveled 4 5 5 4 start fraction, 4, divided by, 5, end fraction of the distance to the

faltersainse [42]

Answer:

0.395 kilometers

Step-by-step explanation:

Please consider the complete question.

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball went into the hole. Martin was standing 79 meters from the hole as he took his second stroke. How many kilometers from the hole was Martin when he started?

Let x represent the distance between hole and start point.

In 1st stroke ball traveled 4/5 of the distance, so 1/5 of the distance was remaining from 2nd stroke to hole. This means the 1/5 of whole distance between start point and hole is equal to 79 meters.

We can represent this information in an equation as:

$\frac{1}{5}x=79$