The more matter in an object, the _____.(1 point)
1 answer:
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Answer:
a) a = 6.1 m/s^2
b) a = 0.98m/s^2
Explanation:
Mass of slab = 40kg
Mass of block = 10kg
Coefficient of static friction (Us) = 0.60
Kinetic coefficient (UK) = 0.40
Horizontal force = 100N
The normal reaction from 40kg slab on 10 kg block = 10*9.81
= 98.1N
Static frictional force = Us*R
= 98.1*0.6
= 58.86N
This is less than the force applied
If 10 kg block will slide on the 40 kg slab, net force = 100 - kinetic force
Kinetic force (Uk*R) = 0.4*98.1
= 39.28N
= 39N
Net force = 100 -39
= 61N
Recall that F = ma
For 10 kg block
a = F/m
a = 61/10
a = 6.1m/s^2
b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4
= 39.24
= 39N
F = ma
a = F/m
For 40kg slab
a = 39/40
a = 0.98m/s^2
Answer:
Original length = 2.97 m
Explanation:
Let the original length of the pendulum be 'L' m
Given:
Acceleration due to gravity (g) = 9.8 m/s²
Original time period of the pendulum (T) = 3.45 s
Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.
New length of the pendulum is,
New time period of the pendulum is,
We know that, the time period of a simple pendulum of length 'L' is given as:
-------------- (1)
So, for the new length, the time period is given as:
------------ (2)
Squaring both the equations and then dividing them, we get:
Now, plug in the given values and calculate 'L'. This gives,
Therefore, the original length of the simple pendulum is 2.97 m