Explanation:
43 holits × (5 gorfs / 3 holits) × (2 queets / 7 gorfs) ≈ 20.5 queets
Answer:
<h2>e. 7.1 MN approx.</h2>
Explanation:
Step one:
given data
density of water= 1000kg/m^3
the dimension of the barge
width= 10m
length= 60m
depth of the boat in the water= 1.2m
Hence the volume occupied by the boat is
volume=10*60*1.2
volume= 720m^2
Step two:
Required is the weight of the barge
we can first find the mass using the relation
density = mass/volume
mass= density*volume
mass= 1000*720
mass= 720000kg
Step three:
Weight =mg
g=9.81m/s^2
W=720000*9.81
W=7063200N
divided by 10^6
W=7.06MN
W=7.1MN approx.
Where's the question?
The weight of the bicycle will be 70kg which means that the bicycle has more friction to the ground.
To determine the mass of gold dissolved in oceans, we must first know the volume of the ocean in liters. To determine its volume, we multiply the area and the depth taking note of the consistency of units. The volume would be 1.38 x 10^18 cubic meters or 1.38x10^21 liters. Then,multiplying this to the concentration, the answer would be 8 x 10^12 grams or 8 billion kg.
Given:
speed of passing pony 5 m/s
frequency of the sound produced: 221 Hz
speed of sound 342 m/s
Let us use the Doppler Shift Formula:
Where the <span>source is moving away from the observer at rest
</span>
f' = (v / v+vs) f
Where, vs<span> = Velocity of the Source,</span>
v = Velocity of sound or light in medium,
f = Real frequency,
f' = Apparent frequency.
f'= [342 m/s / (342 m/s+5m/s)] * 221 Hz
f' = 0.9856 * 221Hz
f' = 217.8176 Hz or 218 Hz
The observed frequency <span>of the hooves after the pony has passed your position is 218 Hz.</span>
