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Aleks04 [339]
3 years ago
13

A jeweler needs 50 ounces of a 21% silver alloy. Find the amount of a 12% silver alloy and the amount of a 24% silver alloy he s

hould mix. Solve using a system of equation.
Need by today!! please show formula and work!!!!
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

  • 12.5 ounces of 12% alloy
  • 37.5 ounces of 24% alloy

Step-by-step explanation:

Let x represent the amount (in ounces) of 24% alloy in the mix. Then the amount of 12% alloy is (50 -x). The amount of silver in the mix is ...

  24%·x + 12%·(50 -x) = 21%·50

  12x = 450 . . . . . . simplify, multiply by 100 (to eliminate %), and subtract 600

  x = 37.5 . . . . . . . divide by 12

The jeweler needs to mix 37.5 ounces of 24% silver alloy with 12.5 ounces of 12% silver alloy to make 50 ounces of 21% silver alloy.

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Step-by-step explanation:

Plug the ordered pair into the equation as (x,y):

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4 = -4 + 8

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Since both sides are equal to each other, then the ordered pair is a solution to the equation.

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2 years ago
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Answer:

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Step-by-step explanation:

The given expression is

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Step 1: Given

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Step-by-step explanation:

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URGENT!!!! WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER!!!!!!
Zepler [3.9K]

geometric sequence

\tt U_n=ar^{n-1}

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