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Aleks04 [339]
3 years ago
13

A jeweler needs 50 ounces of a 21% silver alloy. Find the amount of a 12% silver alloy and the amount of a 24% silver alloy he s

hould mix. Solve using a system of equation.
Need by today!! please show formula and work!!!!
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

  • 12.5 ounces of 12% alloy
  • 37.5 ounces of 24% alloy

Step-by-step explanation:

Let x represent the amount (in ounces) of 24% alloy in the mix. Then the amount of 12% alloy is (50 -x). The amount of silver in the mix is ...

  24%·x + 12%·(50 -x) = 21%·50

  12x = 450 . . . . . . simplify, multiply by 100 (to eliminate %), and subtract 600

  x = 37.5 . . . . . . . divide by 12

The jeweler needs to mix 37.5 ounces of 24% silver alloy with 12.5 ounces of 12% silver alloy to make 50 ounces of 21% silver alloy.

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The correct graph is also attached below.

Step-by-step explanation:

We know when two lines meet at a certain point, the point where they meet is called the point of intersection.

We also know that the point of intersection of two lines is termed as the solution of the system of linear equations.

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