Answer:
Explanation:
Let's do this in Python, we can first generate the random number from 1 to 100. Then compare that with the input number from the guesser.
from random import random
random_0_1 = random()
random_1_100 = 1 if round(100*random_0_1) < 1 else round(100*random_0_1)
for trial in range(3):
guess = input('Guess the number: ')
if guess == random_1_11:
print('You guessed correctly!')
break
else:
print(2 - trial + " remaining try")
local stores in neighborhood do not have computerized cash registers but they may have cameras if they are in a bad neighborhood. inventory is controlled by checking the shelves.
the Qs about computers, servers and clients are for national chain stores. they use clients at each store which are connected to the central servers at HQ. employees need special training as the system is complicated. the whole system is maintained by their IT department.
Answer:
Link Aggregation Control Protocol
Explanation:
Link Aggregation Control Protocol can be used to assist in the formation of port channel bundles of physical links.
Link Aggregation Control Protocol is an IEEE standard defined in IEEE 802.3ad. LACP lets devices send Link Aggregation Control Protocol Data Units (LACPDUs) to each other to establish a link aggregation connection.
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
Answer:
it allows them to work more efficiently, with fewer waisted resources
Explanation:
